Solution sets of linear systems
Homogeneous linear systems
homogeneous: if you can write it in $Ax = 0$ where A is an $m \times n$ matrix and 0 is the zero vector in $\Re^m$
- always has at least one solution (the trivial solution, $x = 0$).
- has a nontrivial solution iff there is a free variable
- if the equation has only one free variable, the solution is a line through the origin
- when there are two or more free variables, it’s a line through the origin
- solution set is $\text{Span} {v_1, \ldots, v_p}$ for suitable vectors
implicit description:
- a simple equation
- e.g. $10x_1 - 3x_2 - 2x_3 = 0$
explicit description (parametric vector form):
- the solution to the equation as a set spanned by u and v
- of the form $x = su + tv$, with $s,t \in \Re$
the solution set of $Ax = 0$ is $x = tv$ with $t \in \Re$.
if $Ax = b$ has a solution, then you get the solution set by translating the solution set of $Ax = 0$ using any particular solution p of $Ax = b$. The set is then $x = p + tv$
Writing a solution set in parametric vector form:
- Row reduce augmented matrix to echelon form
- Express each basic variable in terms of any free variables.
- Write a typical solution x as a vector, with entries depending on the (potential) free variables.
- Decompose x into a linear combination of vectors using free vars as parameters.
Linear independence
linearly independent:
- set of vector equations: iff the vector equation has only the trivial solution ($x_1 = x_2 = x_3 = 0$)
- columns of matrix: iff $Ax = 0$ has only the trivial solution
- one vector: iff v is not the zero vector
- two vectors: if neither of the vectors is a multiple of the other
linearly dependent:
- iff at least one of the vectors is a linear combination of the others
- if there are more vectors than entries in each vector
- if the set contains the zero vector
a set is linearly dependent iff it’s not linearly independent.